Integrand size = 20, antiderivative size = 29 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=\frac {4 \sin ^6(a+b x)}{3 b}-\frac {\sin ^8(a+b x)}{b} \]
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Time = 0.08 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {4373, 2644, 14} \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=\frac {4 \sin ^6(a+b x)}{3 b}-\frac {\sin ^8(a+b x)}{b} \]
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Rule 14
Rule 2644
Rule 4373
Rubi steps \begin{align*} \text {integral}& = 8 \int \cos ^3(a+b x) \sin ^5(a+b x) \, dx \\ & = \frac {8 \text {Subst}\left (\int x^5 \left (1-x^2\right ) \, dx,x,\sin (a+b x)\right )}{b} \\ & = \frac {8 \text {Subst}\left (\int \left (x^5-x^7\right ) \, dx,x,\sin (a+b x)\right )}{b} \\ & = \frac {4 \sin ^6(a+b x)}{3 b}-\frac {\sin ^8(a+b x)}{b} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.66 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=\frac {-72 \cos (2 (a+b x))+12 \cos (4 (a+b x))+8 \cos (6 (a+b x))-3 \cos (8 (a+b x))}{384 b} \]
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Time = 0.93 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.79
method | result | size |
parallelrisch | \(\frac {-72 \cos \left (2 x b +2 a \right )-3 \cos \left (8 x b +8 a \right )+8 \cos \left (6 x b +6 a \right )+12 \cos \left (4 x b +4 a \right )+71}{384 b}\) | \(52\) |
default | \(-\frac {3 \cos \left (2 x b +2 a \right )}{16 b}+\frac {\cos \left (4 x b +4 a \right )}{32 b}+\frac {\cos \left (6 x b +6 a \right )}{48 b}-\frac {\cos \left (8 x b +8 a \right )}{128 b}\) | \(58\) |
risch | \(-\frac {3 \cos \left (2 x b +2 a \right )}{16 b}+\frac {\cos \left (4 x b +4 a \right )}{32 b}+\frac {\cos \left (6 x b +6 a \right )}{48 b}-\frac {\cos \left (8 x b +8 a \right )}{128 b}\) | \(58\) |
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Time = 0.26 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.24 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=-\frac {3 \, \cos \left (b x + a\right )^{8} - 8 \, \cos \left (b x + a\right )^{6} + 6 \, \cos \left (b x + a\right )^{4}}{3 \, b} \]
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Leaf count of result is larger than twice the leaf count of optimal. 359 vs. \(2 (22) = 44\).
Time = 2.01 (sec) , antiderivative size = 359, normalized size of antiderivative = 12.38 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=\begin {cases} \frac {3 x \sin ^{2}{\left (a + b x \right )} \sin ^{3}{\left (2 a + 2 b x \right )}}{16} + \frac {3 x \sin ^{2}{\left (a + b x \right )} \sin {\left (2 a + 2 b x \right )} \cos ^{2}{\left (2 a + 2 b x \right )}}{16} + \frac {3 x \sin {\left (a + b x \right )} \sin ^{2}{\left (2 a + 2 b x \right )} \cos {\left (a + b x \right )} \cos {\left (2 a + 2 b x \right )}}{8} + \frac {3 x \sin {\left (a + b x \right )} \cos {\left (a + b x \right )} \cos ^{3}{\left (2 a + 2 b x \right )}}{8} - \frac {3 x \sin ^{3}{\left (2 a + 2 b x \right )} \cos ^{2}{\left (a + b x \right )}}{16} - \frac {3 x \sin {\left (2 a + 2 b x \right )} \cos ^{2}{\left (a + b x \right )} \cos ^{2}{\left (2 a + 2 b x \right )}}{16} - \frac {\sin ^{2}{\left (a + b x \right )} \sin ^{2}{\left (2 a + 2 b x \right )} \cos {\left (2 a + 2 b x \right )}}{2 b} - \frac {31 \sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (2 a + 2 b x \right )}}{96 b} + \frac {3 \sin {\left (a + b x \right )} \sin ^{3}{\left (2 a + 2 b x \right )} \cos {\left (a + b x \right )}}{16 b} + \frac {\sin {\left (a + b x \right )} \sin {\left (2 a + 2 b x \right )} \cos {\left (a + b x \right )} \cos ^{2}{\left (2 a + 2 b x \right )}}{8 b} - \frac {\cos ^{2}{\left (a + b x \right )} \cos ^{3}{\left (2 a + 2 b x \right )}}{96 b} & \text {for}\: b \neq 0 \\x \sin ^{2}{\left (a \right )} \sin ^{3}{\left (2 a \right )} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.72 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=-\frac {3 \, \cos \left (8 \, b x + 8 \, a\right ) - 8 \, \cos \left (6 \, b x + 6 \, a\right ) - 12 \, \cos \left (4 \, b x + 4 \, a\right ) + 72 \, \cos \left (2 \, b x + 2 \, a\right )}{384 \, b} \]
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Time = 0.38 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.90 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=-\frac {3 \, \sin \left (b x + a\right )^{8} - 4 \, \sin \left (b x + a\right )^{6}}{3 \, b} \]
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Time = 19.08 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.14 \[ \int \sin ^2(a+b x) \sin ^3(2 a+2 b x) \, dx=-\frac {{\cos \left (a+b\,x\right )}^4\,\left ({\cos \left (a+b\,x\right )}^4-\frac {8\,{\cos \left (a+b\,x\right )}^2}{3}+2\right )}{b} \]
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